(x-4)^2=(x-5)(x+5)-3

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Solution for (x-4)^2=(x-5)(x+5)-3 equation: 



(x-4)^2=(x-5)(x+5)-3

We move all terms to the left:

(x-4)^2-((x-5)(x+5)-3)=0

We use the square of the difference formula

x^2+(x-4)^2+25=0

We move all terms containing x to the left, all other terms to the right

x^2+(x-4)^2=-25

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